Calculate the mass of ascorbic acid (text{C}_ | vedclass

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(C) First, calculate the molar mass of ascorbic acid $(	ext{C}_6	ext{H}_8	ext{O}_6)$:
$	ext{Molar mass} = (6 	imes 12) + (8 	imes 1) + (6 	ime

Vedclass · Accepted Answer

$5.077$

Vedclass · Answer

(C) First, calculate the molar mass of ascorbic acid $(	ext{C}_6	ext{H}_8	ext{O}_6)$:
$	ext{Molar mass} = (6 	imes 12) + (8 	imes 1) + (6 	imes 16) = 72 + 8 + 96 = 176 	ext{ g/mol}$.
Use the formula for depression in freezing point: $\Delta T_f = K_f 	imes m$, where $m$ is the molality.
$m = \frac{w 	imes 1000}{M 	imes W_{	ext{solvent}}}$, where $w$ is the mass of solute and $W_{	ext{solvent}}$ is the mass of solvent in grams.
Substituting the given values: $1.5 = 3.9 	imes \frac{w 	imes 1000}{176 	imes 75}$.
Solving for $w$: $w = \frac{1.5 	imes 176 	imes 75}{3.9 	imes 1000} = \frac{19800}{3900} \approx 5.077 	ext{ g}$.

Calculate the mass of ascorbic acid $(\text{C}_6\text{H}_8\text{O}_6)$ to be dissolved in $75 \text{ g}$ of acetic acid to lower its melting point by $1.5^\circ\text{C}$. $[K_f = 3.9 \text{ K kg mol}^{-1}, \text{H} = 1, \text{C} = 12, \text{O} = 16 \text{ amu}]$ (in $\text{ g}$)

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