Calculate the number of atoms in 39.4 g of go | vedclass

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Question

(A) The number of moles $n$ is given by the formula $n = \frac{	ext{mass}}{	ext{molar mass}}$.Given mass $= 39.4$ $g$ and molar mass $= 197$ $g$ $mo

Vedclass · Accepted Answer

$1.2046 	imes 10^{23}$

Vedclass · Answer

(A) The number of moles $n$ is given by the formula $n = \frac{	ext{mass}}{	ext{molar mass}}$.Given mass $= 39.4$ $g$ and molar mass $= 197$ $g$ $mol^{-1}$.$n = \frac{39.4}{197} = 0.2$ $mol$.The number of atoms $N$ is calculated by multiplying the number of moles by Avogadro's number $N_A = 6.023 	imes 10^{23}$ $mol^{-1}$.$N = n 	imes N_A = 0.2 	imes 6.023 	imes 10^{23} = 1.2046 	imes 10^{23}$ atoms.

Calculate the number of atoms in $39.4$ $g$ of gold. The molar mass of gold is $197$ $g$ $mol^{-1}$.

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