Calculate the number of atoms present in $90 \text{ g}$ of a metal that forms a $bcc$ structure. Given: $[\rho \times a^3 = 1.8 \times 10^{-22} \text{ g}]$, where $\rho$ is density and $a$ is the edge length of the unit cell.

  • A
    $4.0 \times 10^{24}$
  • B
    $1.0 \times 10^{24}$
  • C
    $2.0 \times 10^{24}$
  • D
    $3.0 \times 10^{24}$

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