Calculate the solubility of a gas in water at $260 \ mm \ Hg$ and $25^{\circ} C$ if Henry's law constant of the gas is $0.159 \ mol \ dm^{-3} \ atm^{-1}$ at $25^{\circ} C$.
- A$3.8 \times 10^{-2} \ mol \ dm^{-3}$
- B$5.4 \times 10^{-2} \ mol \ dm^{-3}$
- C$2.7 \times 10^{-2} \ mol \ dm^{-3}$
- D$1.2 \times 10^{-2} \ mol \ dm^{-3}$
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The Henry's law constant for the solubility of $N_2$ gas in water at $25 \, ^oC$ is $1 \times 10^5 \, atm$. The mole fraction of $N_2$ in air is $0.8$. Calculate the number of moles of $N_2$ from air that will dissolve in $10 \, moles$ of $H_2O$ at $25 \, ^oC$ and at a total pressure of $5 \, atm$.
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View SolutionCalculate the solubility of a gas having partial pressure $0.15 \ bar$ at $25^{\circ} C$.
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