Calculate the volume of a simple cubic unit cell if the radius of the particle in it is $400 \ pm$.
- A$6.36 \times 10^{-22} \ cm^3$
- B$5.12 \times 10^{-22} \ cm^3$
- C$5.84 \times 10^{-22} \ cm^3$
- D$6.60 \times 10^{-22} \ cm^3$
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Gold has a face-centered cubic $(fcc)$ lattice with an edge length of the unit cube of $407 \, pm$. The diameter of the gold atom is .............. $pm$.
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