Calculate the work done in the oxidation of one mole $HCl_{(g)}$ at $27^{\circ} C$,according to the reaction: $4 HCl_{(g)} + O_{2_{(g)}} \rightarrow 2 Cl_{2_{(g)}} + 2 H_{2}O_{(g)}$ $(R = 8.314 \ J \ K^{-1} \ mol^{-1})$ (in $J$)

  • A
    $2494.2$
  • B
    $623.6$
  • C
    $1247.1$
  • D
    $1870.7$

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