Calculate the wavelength of yellow light having a frequency of $5.09 \times 10^{14} \ Hz$.
(A) The relationship between speed of light $(c)$,wavelength $(\lambda)$,and frequency $(\nu)$ is given by: $c = \lambda \nu$
Rearranging the formula to solve for wavelength: $\lambda = \frac{c}{\nu}$
Given: $c = 3 \times 10^8 \ m \ s^{-1}$ and $\nu = 5.09 \times 10^{14} \ s^{-1}$
$\lambda = \frac{3 \times 10^8 \ m \ s^{-1}}{5.09 \times 10^{14} \ s^{-1}}$
$\lambda = 5.894 \times 10^{-7} \ m$
Converting to nanometers: $\lambda = 589.4 \times 10^{-9} \ m = 589.4 \ nm$
Rearranging the formula to solve for wavelength: $\lambda = \frac{c}{\nu}$
Given: $c = 3 \times 10^8 \ m \ s^{-1}$ and $\nu = 5.09 \times 10^{14} \ s^{-1}$
$\lambda = \frac{3 \times 10^8 \ m \ s^{-1}}{5.09 \times 10^{14} \ s^{-1}}$
$\lambda = 5.894 \times 10^{-7} \ m$
Converting to nanometers: $\lambda = 589.4 \times 10^{-9} \ m = 589.4 \ nm$
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