The momentum (in kg cdot m/s) of a photon hav | vedclass

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(A) The energy of the photon is given as $E = 6 \, MeV = 6 	imes 10^6 \, eV$. Converting energy to Joules: $E = 6 	imes 10^6 	imes 1.6 	imes 10^{-

Vedclass · Accepted Answer

$3.2 	imes 10^{-21}$

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(A) The energy of the photon is given as $E = 6 \, MeV = 6 	imes 10^6 \, eV$. Converting energy to Joules: $E = 6 	imes 10^6 	imes 1.6 	imes 10^{-19} \, J = 9.6 	imes 10^{-13} \, J$. For a photon,the relationship between energy $(E)$ and momentum $(p)$ is $E = pc$,where $c$ is the speed of light $(3 	imes 10^8 \, m/s)$. Therefore,$p = \frac{E}{c} = \frac{9.6 	imes 10^{-13}}{3 	imes 10^8} \, kg \cdot m/s$. $p = 3.2 	imes 10^{-21} \, kg \cdot m/s$.

The momentum (in $kg \cdot m/s$) of a photon having $6 \, MeV$ energy is:

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