Capacitors of capacities $C_1$ and $C_2$ are connected in series. If the combination is connected to a supply of $V$ volt, then the potential difference across capacitor $C_2$ is:

  • A
    $\frac{C_1 + C_2}{C_1} V$
  • B
    $\frac{C_1 V}{C_1 + C_2}$
  • C
    $\frac{C_1 + C_2}{C_2} V$
  • D
    $\frac{C_1 V}{C_1 + C_2}$

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