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(C) Analysis of the given reactions:$(1)$ Benzene reacts with excess $Cl_2$ in the presence of $UV$ light at $500 \ K$ to form benzene hexachloride,wh

Vedclass · Accepted Answer

$2, 4$

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(C) Analysis of the given reactions:$(1)$ Benzene reacts with excess $Cl_2$ in the presence of $UV$ light at $500 \ K$ to form benzene hexachloride,which is non-aromatic.$(2)$ $1,2$-dibromopropane reacts with $alc. KOH$ followed by $NaNH_2$ to form propyne $(CH_3-C \equiv CH)$. Cyclotrimerization of propyne using a red hot iron tube at $873 \ K$ yields $1,3,5$-trimethylbenzene (mesitylene),which is aromatic.$(3)$ $3$-bromocyclobutene reacts with $NaOEt$ to give a substitution product and an elimination product (cyclobutadiene),which dimerizes to a non-aromatic compound.$(4)$ Cyclopentadiene reacts with $NaOMe$ to form the cyclopentadienyl anion,which is aromatic ($6 \pi$ electrons,Huckel's rule).Therefore,reactions $(2)$ and $(4)$ yield aromatic products.

List-$I$	List-$II$
$A$. The reaction of $1,6$-dibromohexane with $Zn$.	$i$. $H_3C-C \equiv CH$
$B$. Reaction of ethanol with concentrated $H_2SO_4$ at $443 \ K$.	$ii$. $H_2C=CH_2$
$C$. Major product in the reaction of propene with $HBr$ in the presence of benzoyl peroxide.	$iii$. $CH_3-CH_2-CH_2-Br$
$D$. The reaction of $1,1$-dibromopropane with $NaNH_2$ at $433 \ K$.	$iv$. Cyclohexane

Choose the correct option$(s)$ that give$(s)$ an aromatic compound as the major product.

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