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(B) The true dip $(\phi)$ is defined in the magnetic meridian,where the horizontal component of the Earth's magnetic field is $B_H$. The relation is g

Vedclass · Accepted Answer

True dip is less than apparent dip.

Vedclass · Answer

(B) The true dip $(\phi)$ is defined in the magnetic meridian,where the horizontal component of the Earth's magnetic field is $B_H$. The relation is given by $	an \phi = \frac{B_V}{B_H}$,where $B_V$ is the vertical component.When the dip circle is rotated by an angle $\alpha$ from the magnetic meridian,the horizontal component becomes $B_H \cos \alpha$,while the vertical component $B_V$ remains unchanged.The apparent dip $(\phi^{\prime})$ is then given by $	an \phi^{\prime} = \frac{B_V}{B_H \cos \alpha} = \frac{	an \phi}{\cos \alpha}$.Since $\cos \alpha \leq 1$,it follows that $	an \phi^{\prime} \geq 	an \phi$. Because the tangent function is increasing in the range $[0, \pi/2]$,we have $\phi^{\prime} \geq \phi$.Therefore,the true dip $(\phi)$ is always less than or equal to the apparent dip $(\phi^{\prime})$.

Choose the correct option regarding the relationship between true dip $(\phi)$ and apparent dip $(\phi^{\prime})$:

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