Compound 'A' reacts with PCl_5 to give 'B',wh | vedclass

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(D) The reaction sequence is as follows:$1$. Compound '$A$' reacts with $PCl_5$ to form '$B$'. Since the final product is propanoic acid $(CH_3CH_2COO

Vedclass · Accepted Answer

Ethyl alcohol

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(D) The reaction sequence is as follows:$1$. Compound '$A$' reacts with $PCl_5$ to form '$B$'. Since the final product is propanoic acid $(CH_3CH_2COOH)$,which contains $3$ carbon atoms,'$B$' must be ethyl chloride $(C_2H_5Cl)$.$2$. Therefore,'$A$' is ethyl alcohol $(C_2H_5OH)$.$3$. The reaction steps are:$C_2H_5OH + PCl_5 	o C_2H_5Cl + POCl_3 + HCl$$C_2H_5Cl + KCN 	o C_2H_5CN + KCl$$C_2H_5CN + 2H_2O + H^+ 	o CH_3CH_2COOH + NH_4^+$

Compound '$A$' reacts with $PCl_5$ to give '$B$',which on treatment with $KCN$ followed by hydrolysis gives propanoic acid as the product. What is '$A$'?

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