Compound A (C_3H_6O) undergoes the following | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The compound $A$ is $CH_3COCH_3$ (acetone),which has the molecular formula $C_3H_6O$. $1$. Reaction with $I_2/NaOH$ (Iodoform test): Acetone react

Vedclass · Accepted Answer

$A = CH_3COCH_3, B = CHI_3, C = CH_3CH_2CH_3$

Vedclass · Answer

(A) The compound $A$ is $CH_3COCH_3$ (acetone),which has the molecular formula $C_3H_6O$. $1$. Reaction with $I_2/NaOH$ (Iodoform test): Acetone reacts with $I_2$ in the presence of $NaOH$ to give a yellow precipitate of iodoform $(CHI_3)$. $CH_3COCH_3 + 3I_2 + 4NaOH \rightarrow CHI_3 + CH_3COONa + 3NaI + 3H_2O$. Here,$B$ is $CHI_3$. $2$. Reaction with $Zn-Hg/HCl$ (Clemmensen reduction): Acetone undergoes reduction to form propane $(CH_3CH_2CH_3)$. $CH_3COCH_3 \xrightarrow{Zn-Hg/HCl} CH_3CH_2CH_3$. Here,$C$ is $CH_3CH_2CH_3$.

Compound $A$ $(C_3H_6O)$ undergoes the following reactions to form $B$ and $C$. Identify $A, B$ and $C$.

Similar Questions

In the reaction sequence $2CH_3CHO$ $\xrightarrow{OH^{-}} A$ $\xrightarrow{\Delta} B$; the product $B$ is

The major product $Q$ of the following reaction scheme is:

The major product of the following reaction is

The order of reactivity of phenyl magnesium bromide $(PhMgBr)$ with the following compounds is:

Consider the given reaction,the product $'X'$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module