Compound 'A' gives a positive test with 2,4-D | vedclass

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(D) $1$. The $2,4-DNP$ test is a characteristic test for carbonyl compounds (aldehydes and ketones). All given options contain a carbonyl group,so the

Vedclass · Accepted Answer

Butan$-2-$one

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(D) $1$. The $2,4-DNP$ test is a characteristic test for carbonyl compounds (aldehydes and ketones). All given options contain a carbonyl group,so they all give a positive $2,4-DNP$ test.$2$. The $I_2/NaOH$ test (Iodoform test) is given by compounds containing a $CH_3CO-$ group or a $CH_3CH(OH)-$ group.$3$. Let us analyze the options:- $Ph-CHO$ (Benzaldehyde): Does not contain a $CH_3CO-$ group.- Diethyl ketone $(CH_3CH_2COCH_2CH_3)$: Does not contain a $CH_3CO-$ group.- Benzophenone $(Ph-CO-Ph)$: Does not contain a $CH_3CO-$ group.- Butan$-2-$one $(CH_3COCH_2CH_3)$: Contains a $CH_3CO-$ group,therefore it gives a positive iodoform test.$4$. Thus,Butan$-2-$one is the correct compound.

Compound '$A$' gives a positive test with $2,4-DNP$ and with $I_2/NaOH$. Compound '$A$' may be:

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