Consider the following statements:
$(A)$ Any physical quantity can have more than one unit.
$(B)$ Any physical quantity has only one dimensional formula.
$(C)$ More than one physical quantity may have the same dimension.
$(D)$ We can add and subtract only those expressions that have the same dimension.
The number of correct statements is:

  • A
    $4$
  • B
    $3$
  • C
    $2$
  • D
    $1$

Explore More

Similar Questions

Identify the pair whose dimensions are equal.

Which of the following pairs of physical quantities does not have the same dimensional formula?

Fill in the blanks:
$(a)$ $1 \ \text{Joule} = \dots \ \text{erg}$
$(b)$ $1 \ \text{eV} = \dots \ \text{Joule}$
$(c)$ $1 \ \text{kWh} = \dots \ \text{Joule}$

Names of units of some physical quantities are given in List-$I$ and their dimensional formulae are given in List-$II$. Match the correct pairs in the lists:
$A$. $Pa \cdot s$$(i)$. $[L^2 T^{-2} K^{-1}]$
$B$. $N \cdot m \cdot K^{-1}$$(ii)$. $[MLT^{-3} K^{-1}]$
$C$. $J \cdot kg^{-1} \cdot K^{-1}$$(iii)$. $[ML^{-1} T^{-1}]$
$D$. $W \cdot m^{-1} \cdot K^{-1}$$(iv)$. $[ML^2 T^{-2} K^{-1}]$

Match the $\text{LIST-I}$ with $\text{LIST-II}$:
$\text{LIST-I}$ $\text{LIST-II}$
$A$. Boltzmann constant $I$. $ML^2 T^{-1}$
$B$. Coefficient of viscosity $II$. $MLT^{-3} K^{-1}$
$C$. Planck's constant $III$. $ML^2 T^{-2} K^{-1}$
$D$. Thermal conductivity $IV$. $ML^{-1} T^{-1}$

Choose the correct answer from the options given below:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo