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(A) Step $1$: Oxidation of ethanol $(CH_3CH_2OH)$ with Jones' reagent or $KMnO_4$ yields ethanoic acid $(CH_3COOH)$.Step $2$: Ethanoic acid reacts wit

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Methane

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(A) Step $1$: Oxidation of ethanol $(CH_3CH_2OH)$ with Jones' reagent or $KMnO_4$ yields ethanoic acid $(CH_3COOH)$.Step $2$: Ethanoic acid reacts with $NaOH$ to form sodium ethanoate $(CH_3COONa)$.Step $3$: Heating sodium ethanoate with soda lime $(NaOH + CaO)$ causes decarboxylation,resulting in the formation of methane $(CH_4)$ and sodium carbonate $(Na_2CO_3)$.Therefore,the major product $P$ is methane.

Consider the following reaction sequence and identify the major product $P$.
$CH_3CH_2OH$ $\xrightarrow[(ii) KMnO_4]{(i) Jones' Reagent}$ $\xrightarrow[(iii) NaOH, CaO, \Delta]{} P$

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Consider the following reaction sequence and identify the major product $P$.$CH_3CH_2OH$ $\xrightarrow[(ii) KMnO_4]{(i) Jones' Reagent}$ $\xrightarrow[(iii) NaOH, CaO, \Delta]{} P$