Consider the following list of reagents:Acidi | vedclass

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(C) The oxidation of $I^-$ to $I_2$ can be performed by acidified $K_2Cr_2O_7$,$CuSO_4$,$H_2O_2$,$Cl_2$,$O_3$,$FeCl_3$,and $HNO_3$.$K_2Cr_2O_7 + 6KI +

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$7$

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(C) The oxidation of $I^-$ to $I_2$ can be performed by acidified $K_2Cr_2O_7$,$CuSO_4$,$H_2O_2$,$Cl_2$,$O_3$,$FeCl_3$,and $HNO_3$.$K_2Cr_2O_7 + 6KI + 7H_2SO_4 \longrightarrow 4K_2SO_4 + Cr_2(SO_4)_3 + 3I_2 + 7H_2O$$2CuSO_4 + 4KI \longrightarrow 2CuI + I_2 + 2K_2SO_4$$H_2O_2 + 2KI \longrightarrow 2KOH + I_2$$2KI + Cl_2 \longrightarrow 2KCl + I_2$$H_2O + 2KI + O_3 \longrightarrow 2KOH + O_2 + I_2$$2FeCl_3 + 2KI \longrightarrow 2KCl + 2FeCl_2 + I_2$$2HNO_3 + 2KI \longrightarrow 2KNO_3 + I_2 + 2NO_2 + 2H_2O$$Na_2S_2O_3$ and alkaline $KMnO_4$ do not oxidise $I^-$ to $I_2$ under these conditions.Thus,the total number of reagents is $7$.

Consider the following list of reagents:
Acidified $K_2Cr_2O_7$,alkaline $KMnO_4$,$CuSO_4$,$H_2O_2$,$Cl_2$,$O_3$,$FeCl_3$,$HNO_3$ and $Na_2S_2O_3$. The total number of reagents that can oxidise aqueous iodide to iodine is

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Consider the following list of reagents:Acidified $K_2Cr_2O_7$,alkaline $KMnO_4$,$CuSO_4$,$H_2O_2$,$Cl_2$,$O_3$,$FeCl_3$,$HNO_3$ and $Na_2S_2O_3$. The total number of reagents that can oxidise aqueous iodide to iodine is