Which of the following is not the correct mat | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For $KHC_2O_4 \cdot H_2C_2O_4$ acting as an acid,the number of replaceable $H^+$ ions is $3$ ($1$ from $KHC_2O_4$ and $2$ from $H_2C_2O_4$).Theref

Vedclass · Accepted Answer

$KHC_2O_4 \cdot H_2C_2O_4$ (As acid) $\rightarrow E = \frac{M}{4}$

Vedclass · Answer

(D) For $KHC_2O_4 \cdot H_2C_2O_4$ acting as an acid,the number of replaceable $H^+$ ions is $3$ ($1$ from $KHC_2O_4$ and $2$ from $H_2C_2O_4$).Therefore,the equivalent weight $E = \frac{M}{3}$.Option $D$ states $E = \frac{M}{4}$,which is incorrect.For $KHC_2O_4 \cdot H_2C_2O_4$ acting as a reducing agent,the total change in oxidation state of carbon is $2 	imes (4-3) + 3 	imes (4-3) = 5$ (or calculation based on total electrons lost),resulting in $E = \frac{M}{4}$ is also context-dependent but $D$ is definitely incorrect as an acid.

Which of the following is not the correct match for equivalent weight :-

Similar Questions

In order to oxidize a mixture of $1 \text{ mole}$ each of $FeC_2O_4$, $Fe_2(C_2O_4)_3$, $FeSO_4$, and $Fe_2(SO_4)_3$ in an acidic medium, the number of moles of $KMnO_4$ required is:

What volume of $O_{2(g)}$ measured at $1 \ atm$ and $273 \ K$ will be formed by the action of $100 \ mL$ of $0.5 \ N \ KMnO_4$ on hydrogen peroxide in an acidic solution? The skeleton equation for the reaction is: $KMnO_4 + H_2SO_4 + H_2O_2 \to K_2SO_4 + MnSO_4 + O_2 + H_2O$.

When $KMnO_4$ solution is titrated with a solution containing $Fe^{2+}$ ions,the indicator used in this titration is

The number of moles of $KMnO_4$ reduced by $1 \ mol$ of $KI$ in basic medium is .............

$KMnO_4$ reacts with ferrous ammonium sulphate according to the equation
$MnO_4^- + 5Fe^{2+} + 8H^+ \to Mn^{2+} + 5Fe^{3+} + 4H_2O$
Here $10 \ mL$ of $0.1 \ M$ $KMnO_4$ is equivalent to:

Vedclass Test Series

Exam Paper Generator

Online Exam Module