Consider the following molecules/species: tro | vedclass

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(C) The bond length is inversely proportional to the bond order.
In acetone $(y)$, the $C=O$ bond has a bond order of $2$.
In tropone $(x)$, the $C=

Vedclass · Accepted Answer

$z > x > y$

Vedclass · Answer

(C) The bond length is inversely proportional to the bond order. In acetone $(y)$, the $C=O$ bond has a bond order of $2$. In tropone $(x)$, the $C=O$ bond is conjugated within a $7$-membered aromatic ring, which gives it a partial single bond character, resulting in a bond order between $1$ and $2$ (lower than $2$, thus higher length than $y$). In the acetate ion $(z)$, resonance leads to two equivalent $C-O$ bonds, each with a bond order of $1.5$. Comparing the bond orders: $y$ $(2)$ > $x$ $(1 < ext{bond order} < 2)$ > $z$ $(1.5)$. Since bond length is inversely proportional to bond order, the order of bond length is $z > x > y$.

Consider the following molecules/species: tropone $(x)$, acetone $(y)$, acetate ion $(z)$. The correct order of carbon-oxygen bond length is:

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