The correct stability order of the following | vedclass

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Question

(B) To determine the stability of resonance structures,we follow these rules:$1$. Structures with more covalent bonds are more stable (complete octets

Vedclass · Accepted Answer

$I > III > II > IV$

Vedclass · Answer

(B) To determine the stability of resonance structures,we follow these rules:$1$. Structures with more covalent bonds are more stable (complete octets).$2$. Structures with fewer formal charges are more stable.$3$. Negative charges should be on more electronegative atoms,and positive charges on less electronegative atoms.Analyzing the structures:$(I)$ $H_2C=N^+=N^-$: Has $4$ bonds,octets are complete for all atoms. It is the most stable.$(III)$ $H_2C^--N^+=N$: Has $4$ bonds,but the negative charge is on the carbon atom (less electronegative than nitrogen). It is the next most stable.$(II)$ $H_2C^+-N=N^-$: Has $3$ bonds,carbon has an incomplete octet. Less stable.$(IV)$ $H_2C^--N=N^+$: Has $3$ bonds,nitrogen has an incomplete octet. Least stable.Thus,the correct order is $I > III > II > IV$.

The correct stability order of the following resonance structures is:

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