The most stable resonating structure of CH_3- | vedclass

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(B) The stability of resonating structures is determined by the following rules:$1$. Structures with more covalent bonds are more stable.$2$. Structur

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$CH_3-\ddot{O}^{+}=CH-CH_2^{-}$

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(B) The stability of resonating structures is determined by the following rules:$1$. Structures with more covalent bonds are more stable.$2$. Structures with complete octets for all atoms are more stable.$3$. Structures with negative charge on a more electronegative atom and positive charge on a less electronegative atom are more stable.$4$. Structures with minimal charge separation are more stable.In the given molecule $CH_3-O^{-}-CH=CH_2$,the oxygen atom has a negative charge. The lone pair on oxygen can participate in resonance with the double bond.However,the structure $CH_3-\ddot{O}^{+}=CH-CH_2^{-}$ involves the movement of electrons from the $O^{-}$ towards the carbon chain,creating a double bond between $O$ and $C$. This structure satisfies the octet rule for all atoms and places the negative charge on the terminal carbon,which is a common resonance contributor. Comparing the options,the structure $CH_3-\ddot{O}^{+}=CH-CH_2^{-}$ is the most stable resonating structure.

The most stable resonating structure of $CH_3-O^{-}-CH=CH_2$ is

Similar Questions

Which of the two structures $A$ $(CH_3COOH)$ and $B$ $(CH_3COO^-)$ given below is more stabilised by resonance? Explain.

The number of resonance structures for $N$ is

The stability order of the following resonance structures is:
$I. CH_2=CH-CH=O$
$II. CH_2^+-CH=CH-O^-$
$III. CH_2^--CH=CH-O^+$

What is resonance energy?

The resonance energy of the following heterocycles is in the order:

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