Consider the following sequence of reactions: | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) $1$. Molar mass of chlorobenzene $(C_6H_5Cl) = (6 	imes 12) + (5 	imes 1) + 35.5 = 112.5 \ g \ mol^{-1}$.
$2$. Molar mass of aniline $(C_6H_5NH_

Vedclass · Accepted Answer

$93$

Vedclass · Answer

(D) $1$. Molar mass of chlorobenzene $(C_6H_5Cl) = (6 	imes 12) + (5 	imes 1) + 35.5 = 112.5 \ g \ mol^{-1}$.
$2$. Molar mass of aniline $(C_6H_5NH_2) = (6 	imes 12) + (7 	imes 1) + 14 = 93 \ g \ mol^{-1}$.
$3$. Since the conversion is complete,the number of moles of chlorobenzene equals the number of moles of aniline (product $B$).
$4$. Moles of chlorobenzene $= \frac{11.25 	imes 10^{-3} \ g}{112.5 \ g \ mol^{-1}} = 10^{-4} \ mol$.
$5$. Moles of aniline $= 10^{-4} \ mol$.
$6$. Mass of aniline $= 10^{-4} \ mol 	imes 93 \ g \ mol^{-1} = 93 	imes 10^{-4} \ g = 93 	imes 10^{-1} \ mg$.
$7$. Therefore,the value is $93$.

List-$I$ (Compounds)	List-$II$ (Reactions)
$A. \ CH_3(CH_2)_3NH_2$	$(i)$ Alkaline hydrolysis
$B. \ CH_3C\equiv CH$	$(ii)$ With $KOH$ (alc.) and $CHCl_3$ produces bad smell
$C. \ CH_3CH_2COOCH_3$	$(iii)$ Gives white ppt. with ammoniacal $AgNO_3$
$D. \ CH_3CH(OH)CH_3$	$(iv)$ With Lucas reagent cloudiness appears after $5 \ minutes$

Similar Questions

Given below are some nitrogen-containing compounds. Each of them is treated with $HCl$ separately. $1.0 \ g$ of the most basic compound will consume $........$ $mg$ of $HCl$. ($Given$ molar mass in $g \ mol^{-1}$: $C:12, H:1, O:16, Cl:35.5$)

Which of the following species would not be involved in the Hoffmann rearrangement shown below?

What are $X$ and $Y$ respectively in the following set of reactions?

The major product of the following reaction is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module