Given below are some nitrogen-containing compounds. Each of them is treated with $HCl$ separately. $1.0 \ g$ of the most basic compound will consume $........$ $mg$ of $HCl$. ($Given$ molar mass in $g \ mol^{-1}$: $C:12, H:1, O:16, Cl:35.5$)

All but one of the following compounds react with aniline to give acetanilide. Which one does not?

The major product $Z$ formed in the following sequence of reactions is:

Match the following:

List-$I$ (Amine)	List-$II$ ($pK_b$ value)
$A$. $N,N$-Dimethylaniline	$I$. $9.30$
$B$. Aniline	$II$. $8.92$
$C$. $N$-Ethylethanamine	$III$. $9.38$
$D$. $N$-Methylaniline	$IV$. $3.00$

The correct answer is

Consider the following sequence of reactions:
Chlorobenzene $\xrightarrow[ii) CO_2, H_3O^{+}]{i) Mg, \text{dry ether}} \text{Benzoic acid}$ $\xrightarrow{NH_3, \Delta} \text{Benzamide (A)}$ $\xrightarrow{Br_2, NaOH} \text{Aniline (B)}$
$11.25 \ mg$ of chlorobenzene will produce $.......... \times 10^{-1} \ mg$ of product $B$.
(Consider the reactions result in complete conversion.)
[Given molar mass of $C, H, O, N$ and $Cl$ as $12, 1, 16, 14$ and $35.5 \ g \ mol^{-1}$ respectively]

Consider the following sequence of reactions to produce major product $(A)$. Molar mass of product $(A)$ is $........... \ g \ mol^{-1}$. (Given molar mass in $g \ mol^{-1}$ of $C : 12, H : 1, O : 16, Br : 80, N : 14, P : 31$)