Consider the following sequence of reactions:
Nitrobenzene $\xrightarrow[(ii) NaNO_2, HCl, 0^{\circ}C]{(i) Sn + HCl} \text{Benzenediazonium chloride}$ $\xrightarrow{(iii) Cu_2Cl_2} \text{Chlorobenzene}$ $\xrightarrow{(iv) Na, \text{Ether}} A$
Molar mass of the product formed $(A)$ is $.............. \ g \ mol^{-1}$.
Nitrobenzene $\xrightarrow[(ii) NaNO_2, HCl, 0^{\circ}C]{(i) Sn + HCl} \text{Benzenediazonium chloride}$ $\xrightarrow{(iii) Cu_2Cl_2} \text{Chlorobenzene}$ $\xrightarrow{(iv) Na, \text{Ether}} A$
Molar mass of the product formed $(A)$ is $.............. \ g \ mol^{-1}$.
- A$154$
- B$150$
- C$180$
- D$120$
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Similar Questions
Match the type of reaction given in Column-$I$ with the reaction in Column-$II$.
Column-$I$ (Reactants) Column-$II$ (Type of Reaction) $(A)$ $C_6H_5NH_2 \xrightarrow{NaNO_2, HX, 273-278 K} C_6H_5N_2^+X^-$ $(i)$ Wurtz-Fittig reaction $(B)$ $C_6H_5N_2^+X^- \xrightarrow{Cu_2X_2} C_6H_5X$ $(ii)$ Diazotization $(C)$ $C_6H_6 + 2Na + RX \xrightarrow{\text{dry ether}} C_6H_5R$ $(iii)$ Sandmeyer reaction $(D)$ $2C_6H_6 + 2Na \xrightarrow{\text{dry ether}} C_6H_5-C_6H_5$ $(iv)$ Fittig reaction
| Column-$I$ (Reactants) | Column-$II$ (Type of Reaction) |
|---|---|
| $(A)$ $C_6H_5NH_2 \xrightarrow{NaNO_2, HX, 273-278 K} C_6H_5N_2^+X^-$ | $(i)$ Wurtz-Fittig reaction |
| $(B)$ $C_6H_5N_2^+X^- \xrightarrow{Cu_2X_2} C_6H_5X$ | $(ii)$ Diazotization |
| $(C)$ $C_6H_6 + 2Na + RX \xrightarrow{\text{dry ether}} C_6H_5R$ | $(iii)$ Sandmeyer reaction |
| $(D)$ $2C_6H_6 + 2Na \xrightarrow{\text{dry ether}} C_6H_5-C_6H_5$ | $(iv)$ Fittig reaction |
Medium
View SolutionThe major product for the following reaction is:
Difficult
View SolutionMatch the following reactions in List-$I$ with their major products in List-$II$.
List-$I$ (Reaction)
List-$II$ (Major product)
$A. \ CH_3CH=CH_2 \xrightarrow{HI}$
$I. \ 1\text{-bromo-}2\text{-phenylethane}$
$B. \ C_6H_5CH_2CH_3 \xrightarrow{Br_2/\Delta}$
$II. \ 1\text{-iodopropane}$
$C. \ C_6H_5CH=CH_2 \xrightarrow{HBr}$
$III. \ 2\text{-iodopropane}$
$IV. \ 1\text{-bromo-}1\text{-phenylethane}$
The correct match is:
| List-$I$ (Reaction) | List-$II$ (Major product) |
|---|---|
| $A. \ CH_3CH=CH_2 \xrightarrow{HI}$ | $I. \ 1\text{-bromo-}2\text{-phenylethane}$ |
| $B. \ C_6H_5CH_2CH_3 \xrightarrow{Br_2/\Delta}$ | $II. \ 1\text{-iodopropane}$ |
| $C. \ C_6H_5CH=CH_2 \xrightarrow{HBr}$ | $III. \ 2\text{-iodopropane}$ |
| $IV. \ 1\text{-bromo-}1\text{-phenylethane}$ |
The correct match is:
DifficultTS EAMCET 2021
View SolutionAn aromatic compound $A$ of formula $C_7H_6Cl_2$ gives $AgCl$ on boiling with alcoholic $AgNO_3$ solution,and yields $C_7H_7OCl$ on treatment with sodium hydroxide. $A$ on oxidation gives a monochlorobenzoic acid which affords only one mononitro derivative. The compound $A$ is :
Medium
View SolutionGiven below are four compounds:
$(a)$ $n$-propyl chloride,
$(b)$ $iso$-propyl chloride,
$(c)$ $sec$-butyl chloride,
$(d)$ $neo$-pentyl chloride.
Percentage of carbon in the one which exhibits optical isomerism is:
$(a)$ $n$-propyl chloride,
$(b)$ $iso$-propyl chloride,
$(c)$ $sec$-butyl chloride,
$(d)$ $neo$-pentyl chloride.
Percentage of carbon in the one which exhibits optical isomerism is:
DifficultJEE MAIN 2026
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