Consider the following statements.p: text{If | vedclass

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(D) $1$. Evaluate $p$: $3^4 = 81$ and $4^3 = 64$. Since $81 > 64$ is true, and $3^3 = 27 > 4^1 = 4$ is also true, the implication $T \implies T$ is $T

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$(p \wedge q) \vee r$

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(D) $1$. Evaluate $p$: $3^4 = 81$ and $4^3 = 64$. Since $81 > 64$ is true, and $3^3 = 27 > 4^1 = 4$ is also true, the implication $T \implies T$ is $T$. Thus, $p$ is True.$2$. Evaluate $q$: The discriminant of $x^2 - 2x + 2 = 0$ is $D = (-2)^2 - 4(1)(2) = 4 - 8 = -4$. Since $D $3$. Evaluate $r$: $r$ is $p \vee 
eg q$. Since $p$ is $T$ and $
eg q$ is $T$, $T \vee T$ is $T$. Thus, $r$ is True.$4$. Check options:$(A)$ $(T \vee F) \wedge T = T \wedge T = T$$(B)$ $T \vee (F \wedge T) = T \vee F = T$$(C)$ $T \wedge (F \vee T) = T \wedge T = T$$(D)$ $(T \wedge F) \vee T = F \vee T = T$Note: All options result in $T$. However, standard logic questions usually have one unique answer. Re-checking $p$: $3^4 > 4^3$ is $81 > 64$ (True). $3^3 > 4^1$ is $27 > 4$ (True). $p$ is True. $q$ is False. $r$ is True. All options evaluate to True. Given the structure, $(D)$ is the most common representation.

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