Consider the isoelectronic species,Na^{+},Mg^ | vedclass

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Question

(B) For isoelectronic species,the ionic radius decreases as the nuclear charge (atomic number) increases.$1$. All given species ($Na^{+}$,$Mg^{2+}$,$F

Vedclass · Accepted Answer

$Mg^{2+} < Na^{+} < F^{-} < O^{2-}$

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(B) For isoelectronic species,the ionic radius decreases as the nuclear charge (atomic number) increases.$1$. All given species ($Na^{+}$,$Mg^{2+}$,$F^{-}$,$O^{2-}$) have $10$ electrons.$2$. Their atomic numbers are: $O (8)$,$F (9)$,$Na (11)$,$Mg (12)$.$3$. As the nuclear charge increases,the attraction of the nucleus for the electrons increases,causing the ionic radius to decrease.$4$. The order of increasing atomic number is $O^{2-} (8) $5$. Therefore,the order of increasing ionic radii is $Mg^{2+} < Na^{+} < F^{-} < O^{2-}$.

$A$. Element	$B$. Atomic Radius $(pm)$
$A$. $Be$	$I$. $74$
$B$. $C$	$II$. $77$
$C$. $O$	$III$. $66$
$D$. $B$	$IV$. $88$
$E$. $N$	$V$. $111$

Consider the isoelectronic species,$Na^{+}$,$Mg^{2+}$,$F^{-}$,and $O^{2-}$. The correct order of increasing ionic radii is:

Similar Questions

Match the elements in Column-$A$ with their correct atomic radii in Column-$B$ (in $pm$).

$A$. Element $B$. Atomic Radius $(pm)$

$A$. $Be$ $I$. $74$

$B$. $C$ $II$. $77$

$C$. $O$ $III$. $66$

$D$. $B$ $IV$. $88$

$E$. $N$ $V$. $111$

Which one of the following ions has the highest value of ionic radius?

Which one of the following has the largest ionic radius?

The correct order of the ionic radii of $O^{2-}, N^{3-}, F^{-}, Mg^{2+}, Na^{+}$ and $Al^{3+}$ is

The correct order of the decreasing ionic radii among the following isoelectronic species is

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