Consider the reaction K_2[Ni(CN)_4] + 4K + 4N | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction is $K_2[Ni(CN)_4] + 4K + 4NH_3 	o K_4[Ni(NH_3)_4] + 4KCN$.Complex $A$ is $K_4[Ni(NH_3)_4]$.In $K_4[Ni(NH_3)_4]$,the oxidation state

Vedclass · Accepted Answer

Complex is $sp^3$ hybridised & diamagnetic

Vedclass · Answer

(A) The reaction is $K_2[Ni(CN)_4] + 4K + 4NH_3 	o K_4[Ni(NH_3)_4] + 4KCN$.Complex $A$ is $K_4[Ni(NH_3)_4]$.In $K_4[Ni(NH_3)_4]$,the oxidation state of $Ni$ is $0$ ($d^{10}$ configuration).Since $Ni(0)$ has a $d^{10}$ configuration,all $d$-orbitals are filled.Therefore,it undergoes $sp^3$ hybridisation to form a tetrahedral geometry.Since all electrons are paired in the $d^{10}$ configuration,the complex is diamagnetic.Thus,the complex is $sp^3$ hybridised and diamagnetic.

Consider the reaction $K_2[Ni(CN)_4] + 4K + 4NH_3 \to A$ (complex $A$).
Complex $A$ gives five ions in aqueous solution. Choose the $CORRECT$ statements.

Similar Questions

The complex ion which has no $d$ electrons in the central metal atom is

Which of the following electronic configurations shall form an octahedral complex?

How many unpaired electrons are present in $Ni^{2+}$?

Considering $H_2O$ as a weak field ligand,the number of unpaired electrons in $[Mn(H_2O)_6]^{2+}$ will be (Atomic number of $Mn = 25$).

How many unpaired electrons are present in the central metal ion of $[CoCl_4]^{2-}$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Consider the reaction $K_2[Ni(CN)_4] + 4K + 4NH_3 \to A$ (complex $A$).Complex $A$ gives five ions in aqueous solution. Choose the $CORRECT$ statements.