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(A) The velocity of a particle in a wave is given by the relation: $v_p = -(	ext{slope}) 	imes v_{	ext{wave}}$.Since the wave is traveling in the p

Vedclass · Accepted Answer

The particle $A$ is moving in the $-ve$ $y$-direction and particle $B$ is moving in the $+ve$ $y$-direction.

Vedclass · Answer

(A) The velocity of a particle in a wave is given by the relation: $v_p = -(	ext{slope}) 	imes v_{	ext{wave}}$.Since the wave is traveling in the positive $x$-direction,$v_{	ext{wave}}$ is positive.At point $A$,the slope of the wave displacement curve is positive. Therefore,$v_p = -(	ext{positive}) 	imes (	ext{positive}) = 	ext{negative}$. Thus,particle $A$ is moving in the $-ve$ $y$-direction.At point $B$,the slope of the wave displacement curve is negative. Therefore,$v_p = -(	ext{negative}) 	imes (	ext{positive}) = 	ext{positive}$. Thus,particle $B$ is moving in the $+ve$ $y$-direction.Hence,particle $A$ moves in the $-ve$ $y$-direction and particle $B$ moves in the $+ve$ $y$-direction.

Consider the snapshot of a wave traveling in the positive $x$-direction.

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