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(A) Intensity of radiation is defined as the energy incident per unit area per unit time: $I = \frac{E}{A \cdot t}$.For a photon of frequency $f$, the

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$2: 3$

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(A) Intensity of radiation is defined as the energy incident per unit area per unit time: $I = \frac{E}{A \cdot t}$.For a photon of frequency $f$, the energy is $E = hf$. Thus, the total energy incident is $E_{total} = N \cdot hf$.For surface $A$: $I_A = \frac{n \cdot hf}{A \cdot t}$.For surface $B$: $I_B = \frac{(2n) \cdot h(3f)}{A \cdot (4t)} = \frac{6nhf}{4At} = \frac{3nhf}{2At}$.Taking the ratio: $\frac{I_A}{I_B} = \frac{nhf}{At} \cdot \frac{2At}{3nhf} = \frac{2}{3}$.Therefore, the ratio is $2: 3$.

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