Consider two identical galvanometers and two | vedclass

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(D) For a voltmeter,the range $V = I_g(R_G + R_{ext})$. To maximize $V$,we need to maximize the total resistance $R_{total}$. Connecting all component

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$A, C$

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(D) For a voltmeter,the range $V = I_g(R_G + R_{ext})$. To maximize $V$,we need to maximize the total resistance $R_{total}$. Connecting all components in series gives $R_{total} = 2R_G + 2R$. This is the maximum possible resistance,so option $(A)$ is correct for voltage range.For an ammeter,the range $I = I_g(1 + R_G/R_s)$. To maximize $I$,we need to minimize the equivalent resistance of the shunt $R_s$. Connecting all components in parallel gives the minimum equivalent resistance,which maximizes the current range. Thus,option $(C)$ is correct for current range.Therefore,the correct options are $(A)$ and $(C)$.

Consider two identical galvanometers and two identical resistors with resistance $R$. If the internal resistance of the galvanometers is $R_G < R/2$,which of the following configurations yield the maximum voltage range and maximum current range?

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