Construct a triangle $ABC$ in which $BC = 7\,cm, \angle B = 75^\circ$ and $AB + AC = 13\,cm$.

(N/A) Steps of construction:
$I.$ Draw a ray $BX$.
$II.$ From ray $BX$,cut off a line segment $BC = 7\,cm$.
$III.$ At point $B$,construct an angle $\angle CBY = 75^\circ$.
$IV.$ From ray $BY$,cut off a line segment $BD = 13\,cm$.
$V.$ Join $D$ and $C$.
$VI.$ Construct the perpendicular bisector of the line segment $DC$. Let this bisector intersect $BD$ at point $A$.
$VII.$ Join $AC$.
Thus,$\Delta ABC$ is the required triangle.