Construct a triangle $PQR$ in which $QR = 6 \, cm, \angle Q = 60^{\circ}$ and $PR - PQ = 2 \, cm$.

(N/A) Steps of construction:
$I.$ Draw a ray $\overrightarrow{QX}$.
$II.$ From $\overrightarrow{QX}$,cut off $QR = 6 \, cm$.
$III.$ Construct a line $YQY'$ such that $\angle RQY = 60^{\circ}$.
$IV.$ Cut off $QS = 2 \, cm$ (from $\overrightarrow{QY'}$).
$V.$ Join $S$ and $R$.
$VI.$ Draw $MN$,the perpendicular bisector of $SR$,which intersects $QY$ at $P$.
$VII.$ Join $P$ and $R$.
Thus,$PQR$ is the required triangle.