Convert the following into moles:(a) 12, g of | vedclass

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(A) For oxygen gas $(O_2)$:Molar mass of $O_2 = 16 	imes 2 = 32\, 	ext{g/mol}$.Number of moles $= \frac{	ext{Given mass}}{	ext{Molar mass}} = \fra

Vedclass · Accepted Answer

$0.375\, 	ext{mol}$,$1.11\, 	ext{mol}$ and $0.5\, 	ext{mol}$

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(A) For oxygen gas $(O_2)$:Molar mass of $O_2 = 16 	imes 2 = 32\, 	ext{g/mol}$.Number of moles $= \frac{	ext{Given mass}}{	ext{Molar mass}} = \frac{12\, 	ext{g}}{32\, 	ext{g/mol}} = 0.375\, 	ext{mol}$.$(b)$ For water $(H_2O)$:Molar mass of $H_2O = (2 	imes 1) + 16 = 18\, 	ext{g/mol}$.Number of moles $= \frac{20\, 	ext{g}}{18\, 	ext{g/mol}} \approx 1.11\, 	ext{mol}$.$(c)$ For carbon dioxide $(CO_2)$:Molar mass of $CO_2 = 12 + (2 	imes 16) = 44\, 	ext{g/mol}$.Number of moles $= \frac{22\, 	ext{g}}{44\, 	ext{g/mol}} = 0.5\, 	ext{mol}$.

Convert the following into moles:
$(a)$ $12\, g$ of oxygen gas
$(b)$ $20\, g$ of water
$(c)$ $22\, g$ of carbon dioxide.

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Convert the following into moles:$(a)$ $12\, g$ of oxygen gas$(b)$ $20\, g$ of water$(c)$ $22\, g$ of carbon dioxide.