The correct increasing order for the waveleng | vedclass

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Question

(B) The energy of absorbed light $(\Delta_o)$ is inversely proportional to the wavelength of absorption $(\lambda)$: $\Delta_o \propto \frac{1}{\lambd

Vedclass · Accepted Answer

$[Co(H_2O)_6]^{3+}, [Co(NH_3)_6]^{3+}, [Co(en)_3]^{3+}$

Vedclass · Answer

(B) The energy of absorbed light $(\Delta_o)$ is inversely proportional to the wavelength of absorption $(\lambda)$: $\Delta_o \propto \frac{1}{\lambda}$.
Stronger ligands cause greater crystal field splitting $(\Delta_o)$,which corresponds to higher energy and shorter wavelength of absorption.
The spectrochemical series for the given ligands is: $H_2O < NH_3 < en$.
As the ligand strength increases,the splitting energy $(\Delta_o)$ increases,and therefore the absorbed wavelength $(\lambda)$ decreases.
Thus,the increasing order of wavelength is: $[Co(H_2O)_6]^{3+} < [Co(NH_3)_6]^{3+} < [Co(en)_3]^{3+}$.

$I$. $H_2O$	$II$. $CO$
$III$. $NH_3$	$IV$. $I^{-}$
$V$. $F^{-}$

The correct increasing order for the wavelengths of absorption in the visible region for the complexes of $Co^{3+}$ is:

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