Explain the origin of colour in coordination compounds.

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(N/A) When white light passes through a coordination compound,a portion of the visible spectrum is absorbed. The light that emerges is no longer white; its colour is the complementary colour of the light that was absorbed.
The complementary colour is generated from the remaining wavelengths of the visible spectrum.
For example,if a sample absorbs green light,it appears red. This phenomenon can be explained using Crystal Field Theory $(CFT)$.
Consider the complex $[Ti(H_{2}O)_{6}]^{3+}$,which is violet in colour. This complex has a $d^{1}$ configuration. The single electron occupies the $t_{2g}$ level in the ground state. Upon absorbing light,this electron undergoes a $d-d$ transition to the higher energy $e_{g}$ orbital. The energy of the absorbed photon corresponds to the crystal field splitting energy $(\Delta_{o})$,which falls within the visible region.

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Similar Questions

The correct order of the wavelength of light absorbed by the following complexes is,
$A. [Co(NH_3)_6]^{3+}$
$B. [Co(CN)_6]^{3-}$
$C. [Cu(H_2O)_4]^{2+}$
$D. [Ti(H_2O)_6]^{3+}$
Choose the correct answer from the options given below:

For which of the following pairs of complexes is the crystal field splitting energy $\Delta_0$ for $II > \Delta_0$ for $I$?
$I$ $II$
$(a). [Cr(H_2O)_6]^{2+}$ $[Cr(H_2O)_6]^{3+}$
$(b). [Fe(H_2O)_6]^{3+}$ $[Fe(CN)_6]^{3-}$
$(c). [Fe(CN)_6]^{3-}$ $[Ru(CN)_6]^{3-}$
$(d). [NiF_6]^{4-}$ $[NiF_6]^{2-}$

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Identify the correct trend given below.
(Atomic No. $= Ti : 22, Cr : 24$ and $Mo : 42$)

$A$ $[M(H_2O)_6]^{2+}$ complex typically absorbs at around $600 \ nm$. It is allowed to react with ammonia to form a new complex $[M(NH_3)_6]^{2+}$ that should have absorption at ....... $nm$.

Which ligand among the following has the highest splitting power of $d$-orbitals of the central metal ion?

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