The correct order of the wavelength of light | vedclass

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(B) The energy of absorbed light $(E)$ is inversely proportional to the wavelength $(\lambda)$ according to the relation $E = \frac{hc}{\lambda}$.
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Vedclass · Accepted Answer

$B < A < D < C$

Vedclass · Answer

(B) The energy of absorbed light $(E)$ is inversely proportional to the wavelength $(\lambda)$ according to the relation $E = \frac{hc}{\lambda}$. Stronger ligands cause a larger crystal field splitting $(\Delta_0)$,which leads to the absorption of light with higher energy and shorter wavelength. The spectrochemical series for the ligands is: $CN^{-} > NH_3 > H_2O$. Comparing the complexes: $1. [Co(CN)_6]^{3-}$: Strongest ligand $(CN^{-})$,largest $\Delta_0$,shortest $\lambda$. $2. [Co(NH_3)_6]^{3+}$: Strong ligand $(NH_3)$,intermediate $\Delta_0$. $3. [Ti(H_2O)_6]^{3+}$: Weak ligand $(H_2O)$,smaller $\Delta_0$. $4. [Cu(H_2O)_4]^{2+}$: Weak ligand $(H_2O)$,smallest $\Delta_0$ among these,longest $\lambda$. Thus,the order of wavelength of light absorbed is $B < A < D < C$.

The correct order of the wavelength of light absorbed by the following complexes is,
$A. [Co(NH_3)_6]^{3+}$
$B. [Co(CN)_6]^{3-}$
$C. [Cu(H_2O)_4]^{2+}$
$D. [Ti(H_2O)_6]^{3+}$
Choose the correct answer from the options given below:

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The correct order of the wavelength of light absorbed by the following complexes is, $A. [Co(NH_3)_6]^{3+}$ $B. [Co(CN)_6]^{3-}$ $C. [Cu(H_2O)_4]^{2+}$ $D. [Ti(H_2O)_6]^{3+}$ Choose the correct answer from the options given below: