The correct order of ligands arranged in increasing field strength.
- A$Cl^{-} < OH^{-} < Br^{-} < CN^{-}$
- B$F^{-} < Br^{-} < I^{-} < NH_3$
- C$Br^{-} < F^{-} < H_2O < NH_3$
- D$H_2O < OH^{-} < CN^{-} < NH_3$
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Similar Questions
The correct order of the wavelength of light absorbed by the following complexes is,
$A. [Co(NH_3)_6]^{3+}$
$B. [Co(CN)_6]^{3-}$
$C. [Cu(H_2O)_4]^{2+}$
$D. [Ti(H_2O)_6]^{3+}$
Choose the correct answer from the options given below:
$A. [Co(NH_3)_6]^{3+}$
$B. [Co(CN)_6]^{3-}$
$C. [Cu(H_2O)_4]^{2+}$
$D. [Ti(H_2O)_6]^{3+}$
Choose the correct answer from the options given below:
MediumNEET 2025
View SolutionThe homoleptic and octahedral complex of $Co^{2+}$ and $H_2O$ has $.......$ unpaired electron$(s)$ in the $t_{2g}$ set of orbitals.
DifficultJEE MAIN 2023
View SolutionThe $d-$orbital electronic configuration of the complex among $[Co(en)_3]^{3+}$,$[CoF_6]^{3-}$,$[Mn(H_2O)_6]^{2+}$ and $[Zn(H_2O)_6]^{2+}$ that has the highest $CFSE$ is $:$
The tetrahedral crystal field splitting energy is equal to ................. of the octahedral crystal field splitting energy.
Easy
View SolutionWhich of the following represents the correct increasing order of crystal field splitting energy?
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