The correct order of strength of pi- bond(s) | vedclass

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(C) The strength of $\pi-$ bonds depends on the extent of orbital overlap. $I$. In $BO_3^{3-}, CO_3^{2-}, NO_3^{-}$,the central atoms are $B, C, N$ re

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$I, II, III$

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(C) The strength of $\pi-$ bonds depends on the extent of orbital overlap. $I$. In $BO_3^{3-}, CO_3^{2-}, NO_3^{-}$,the central atoms are $B, C, N$ respectively. As the electronegativity of the central atom increases,the effective nuclear charge increases,leading to better $p\pi-p\pi$ overlap. Thus,the order is $BO_3^{3-} $II$. In oxoanions like $ClO_4^{-}, SO_4^{2-}, PO_4^{3-}$,the $\pi-$ bond strength increases with the increase in the electronegativity of the central atom,which facilitates better $p\pi-d\pi$ overlap. Thus,$ClO_4^{-} > SO_4^{2-} > PO_4^{3-}$. $III$. In boron trihalides,back bonding occurs via $p\pi-p\pi$ overlap. The extent of overlap is $2p-2p$ $(BF_3)$ > $2p-3p$ $(BCl_3)$ > $2p-4p$ $(BBr_3)$. Thus,$BF_3 > BCl_3 > BBr_3$. $IV$. In $AlCl_3$,the $Al$ atom has $3p$ orbitals,while in $BCl_3$,$B$ has $2p$ orbitals. The $2p-3p$ overlap in $BCl_3$ is stronger than the $3p-3p$ overlap in $AlCl_3$. Thus,$BCl_3 > AlCl_3$. Therefore,statements $I, II,$ and $III$ are correct.

The correct order of strength of $\pi-$ bond$(s)$ is:
$I$. $BO_3^{-3} < CO_3^{-2} < NO_3^{-}$
$II$. $ClO_4^{-} > SO_4^{-2} > PO_4^{-3}$
$III$. $BF_3 > BCl_3 > BBr_3$
$IV$. $AlCl_3 < BCl_3$

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The correct order of strength of $\pi-$ bond$(s)$ is:$I$. $BO_3^{-3} < CO_3^{-2} < NO_3^{-}$$II$. $ClO_4^{-} > SO_4^{-2} > PO_4^{-3}$$III$. $BF_3 > BCl_3 > BBr_3$$IV$. $AlCl_3 < BCl_3$