The correct sequence of CO bond order in the | vedclass

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(B) The $CO$ bond order is inversely proportional to the extent of back-bonding from the metal to the $CO$ ligand $(M 	o CO)$.$1$. In $H_3B \leftarro

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$R > Q > P > S$

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(B) The $CO$ bond order is inversely proportional to the extent of back-bonding from the metal to the $CO$ ligand $(M 	o CO)$.$1$. In $H_3B \leftarrow CO$,there is no back-bonding; instead,$B$ acts as a Lewis acid,which can increase the $CO$ bond order slightly above $3.0$.$2$. In free $CO$,the bond order is $3.0$.$3$. In $Fe(CO)_5$,back-bonding occurs from $Fe$ to $CO$,reducing the $CO$ bond order to less than $3.0$.$4$. In $[Mn(CO)_5]^-$,the negative charge on the metal center increases the electron density,leading to stronger back-bonding compared to $Fe(CO)_5$,thus further reducing the $CO$ bond order.Therefore,the correct sequence of $CO$ bond order is $R > Q > P > S$.

$LIST-I$ (Substances)	$LIST-II$ (Element Present)
$A$. Ziegler catalyst	$I$. Rhodium
$B$. Blood pigment	$II$. Cobalt
$C$. Wilkinson catalyst	$III$. Iron
$D$. Vitamin $B_{12}$	$IV$. Titanium

The correct sequence of $CO$ bond order in the given compounds is:
$(P) \ Fe(CO)_5, (Q) \ CO, (R) \ H_3B \leftarrow CO, (S) \ [Mn(CO)_5]^-$

Similar Questions

The molecular formula of Wilkinson catalyst,used in the hydrogenation of alkenes is -

Match List-$I$ with List-$II$:

$LIST-I$ (Substances) $LIST-II$ (Element Present)

$A$. Ziegler catalyst $I$. Rhodium

$B$. Blood pigment $II$. Cobalt

$C$. Wilkinson catalyst $III$. Iron

$D$. Vitamin $B_{12}$ $IV$. Titanium

Choose the correct answer from the options given below:

If the bond length of $CO$ bond in carbon monoxide is $1.128 \ \mathring{A}$,then what is the value of $CO$ bond length in $Fe(CO)_5$?

In the cobalt-carbonyl complex: $[Co_{2}(CO)_{8}]$,the number of $Co-Co$ bonds is "$X$" and the number of terminal $CO$ ligands is "$Y$". Find the value of $X + Y$.

Which of the following compounds is used as an antiknock agent?

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The correct sequence of $CO$ bond order in the given compounds is:$(P) \ Fe(CO)_5, (Q) \ CO, (R) \ H_3B \leftarrow CO, (S) \ [Mn(CO)_5]^-$