Correct statement for CeO_2 is/are:1. It is d | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In $CeO_2$,Cerium is in the $+4$ oxidation state $(Ce^{4+})$.The electronic configuration of $Ce$ $(Z=58)$ is $[Xe] 4f^1 5d^1 6s^2$. Therefore,$Ce

Vedclass · Accepted Answer

$1, 2$ and $3$

Vedclass · Answer

(D) In $CeO_2$,Cerium is in the $+4$ oxidation state $(Ce^{4+})$.The electronic configuration of $Ce$ $(Z=58)$ is $[Xe] 4f^1 5d^1 6s^2$. Therefore,$Ce^{4+}$ has the configuration $[Xe] 4f^0$.$1$. Since there are no unpaired electrons in the $4f$ orbital,$CeO_2$ is diamagnetic. This statement is correct.$2$. $Ce^{4+}$ has a strong tendency to gain an electron to return to the more stable $+3$ oxidation state $(Ce^{3+})$. Thus,it acts as a good oxidising agent. This statement is correct.$3$. Due to the absence of $f-f$ transitions ($4f^0$ configuration),$CeO_2$ is colourless. This statement is correct.Therefore,all three statements are correct.

Correct statement for $CeO_2$ is/are:
$1$. It is diamagnetic in nature.
$2$. It is a good oxidising agent.
$3$. It is a colourless compound.

Similar Questions

Which one of the following is known as lunar caustic when in fused state?

Which of the following statements is incorrect for $KMnO_4$?

$Cu_2Cl_2$ with $HCl$ in the presence of oxidizing agents gives:

Which one of the following species does not represent a cationic species of vanadium formed in an aqueous solution?

An aqueous solution of $FeSO_4$,$Al_2(SO_4)_3$ and chrome alum is heated with excess of $Na_2O_2$ and filtered. The materials obtained are

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Correct statement for $CeO_2$ is/are:$1$. It is diamagnetic in nature.$2$. It is a good oxidising agent.$3$. It is a colourless compound.