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(D) To determine the number of lone pairs on the central atom,we use the formula: $	ext{Lone pairs} = \frac{1}{2} (V - B)$,where $V$ is the number of

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$1$,$0$,and $2$ lone pairs of central atom respectively

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(D) To determine the number of lone pairs on the central atom,we use the formula: $	ext{Lone pairs} = \frac{1}{2} (V - B)$,where $V$ is the number of valence electrons of the central atom and $B$ is the number of bonding electrons (assuming single bonds).$1$. For $SF_4$: Sulfur $(S)$ has $6$ valence electrons. It forms $4$ bonds with $F$ atoms. $	ext{Lone pairs} = \frac{1}{2} (6 - 4) = 1$.$2$. For $CF_4$: Carbon $(C)$ has $4$ valence electrons. It forms $4$ bonds with $F$ atoms. $	ext{Lone pairs} = \frac{1}{2} (4 - 4) = 0$.$3$. For $XeF_4$: Xenon $(Xe)$ has $8$ valence electrons. It forms $4$ bonds with $F$ atoms. $	ext{Lone pairs} = \frac{1}{2} (8 - 4) = 2$.Thus,the number of lone pairs are $1$,$0$,and $2$ respectively. The correct option is $D$.

List-$I$ Molecule/ion	List-$II$ Bond pair : lone pair (on the central atom)
$A. ICl_2^-$	$I. 4 : 2$
$B. H_2O$	$II. 4 : 1$
$C. SO_2$	$III. 2 : 3$
$D. XeF_4$	$IV. 2 : 2$

List-$I$ (Shape)	List-$II$ (Molecules)
$A$. $T$-shaped	$I$. $XeF_4$
$B$. Trigonal planar	$II$. $SF_4$
$C$. Square planar	$III$. $ClF_3$
$D$. See-saw	$IV$. $BF_3$

The correct statement regarding the number of lone pairs on the central atoms of the molecules $SF_4$,$CF_4$,and $XeF_4$ is:

Similar Questions

Which among the following concepts is $NOT$ introduced by $V.B.$ Theory?

Match the List-$I$ with List-$II$.

List-$I$ Molecule/ion List-$II$ Bond pair : lone pair (on the central atom)

$A. ICl_2^-$ $I. 4 : 2$

$B. H_2O$ $II. 4 : 1$

$C. SO_2$ $III. 2 : 3$

$D. XeF_4$ $IV. 2 : 2$

Choose the correct answer from the options given below:

Which is the $CORRECT$ relation of bond angles?

What is the shape of $ClO_3^-$?

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