Match the List-I with List-II. List-I Mo | vedclass

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(B) To determine the number of bond pairs $(BP)$ and lone pairs $(LP)$ on the central atom:$A. ICl_2^-$: Iodine $(I)$ has $7$ valence electrons $+ 1$

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$A-III, B-IV, C-II, D-I$

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(B) To determine the number of bond pairs $(BP)$ and lone pairs $(LP)$ on the central atom:$A. ICl_2^-$: Iodine $(I)$ has $7$ valence electrons $+ 1$ (negative charge) $= 8$. It forms $2$ single bonds with $Cl$. $BP = 2$. Remaining electrons $= 8 - 2 = 6$,which means $3$ lone pairs. $LP = 3$. Ratio $2:3$ (Matches $III$).$B. H_2O$: Oxygen $(O)$ has $6$ valence electrons. It forms $2$ single bonds with $H$. $BP = 2$. Remaining electrons $= 6 - 2 = 4$,which means $2$ lone pairs. $LP = 2$. Ratio $2:2$ (Matches $IV$).$C. SO_2$: Sulfur $(S)$ has $6$ valence electrons. It forms $2$ double bonds with $O$. Total shared electrons in bonds $= 4$. $BP = 4$. Remaining electrons $= 6 - 4 = 2$,which means $1$ lone pair. $LP = 1$. Ratio $4:1$ (Matches $II$).$D. XeF_4$: Xenon $(Xe)$ has $8$ valence electrons. It forms $4$ single bonds with $F$. $BP = 4$. Remaining electrons $= 8 - 4 = 4$,which means $2$ lone pairs. $LP = 2$. Ratio $4:2$ (Matches $I$).Therefore,the correct matching is $A-III, B-IV, C-II, D-I$.

List-$I$ Molecule/ion	List-$II$ Bond pair : lone pair (on the central atom)
$A. ICl_2^-$	$I. 4 : 2$
$B. H_2O$	$II. 4 : 1$
$C. SO_2$	$III. 2 : 3$
$D. XeF_4$	$IV. 2 : 2$

Match the List-$I$ with List-$II$.

List-$I$ Molecule/ion List-$II$ Bond pair : lone pair (on the central atom)

$A. ICl_2^-$ $I. 4 : 2$

$B. H_2O$ $II. 4 : 1$

$C. SO_2$ $III. 2 : 3$

$D. XeF_4$ $IV. 2 : 2$

Choose the correct answer from the options given below:

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Match the List-$I$ with List-$II$. List-$I$ Molecule/ion List-$II$ Bond pair : lone pair (on the central atom) $A. ICl_2^-$ $I. 4 : 2$ $B. H_2O$ $II. 4 : 1$ $C. SO_2$ $III. 2 : 3$ $D. XeF_4$ $IV. 2 : 2$ Choose the correct answer from the options given below: