The $O-N-O$ bond angle is maximum in

According to $VSEPR$ theory,the most probable shape of the molecule having $4$ electron pairs in the outer shell of the central atom is

$XeF_4$ is square planar while $XeF_6$ has a distorted octahedral structure. What is the correct explanation for this observation?

Give the correct order of initials $T$ or $F$ for following statements. Use $T$ if statement is true and $F$ if it is false:
$(I)$ The order of repulsion between different pair of electrons is $lp-lp > lp-bp > bp-bp$.
$(II)$ In general,as the number of lone pair of electrons on the central atom increases,the deviation of the bond angle from the normal bond angle increases.
$(III)$ The number of lone pairs on $O$ in $H_2O$ is $2$,while on $N$ in $NH_3$ is $1$.
$(IV)$ The structures of xenon fluorides and xenon oxyfluorides could not be explained on the basis of $VSEPR$ theory.

Consider the following reaction:
$2Se_2Cl_2 \to 3Se + SeCl_4$
Choose the $CORRECT$ option regarding the product $SeCl_4$ (referred to as $A$ in the options).

Which of the following substances has the minimum bond angle?