Define 'average speed'. An object moves with a uniform speed of $10\, m s^{-1}$ for $5\, s$ and then with a uniform speed of $5\, m s^{-1}$ for $10\, s$. Find its average speed.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
$(6.67\, m s^{-1})$ Average speed of an object is defined as the total distance travelled divided by the total time taken.
Step $1$: Calculate the total distance covered.
Distance for the first part $= 10\, m s^{-1} \times 5\, s = 50\, m$.
Distance for the second part $= 5\, m s^{-1} \times 10\, s = 50\, m$.
Total distance $= 50\, m + 50\, m = 100\, m$.
Step $2$: Calculate the total time taken.
Total time $= 5\, s + 10\, s = 15\, s$.
Step $3$: Calculate the average speed.
Average speed $= \frac{\text{Total distance}}{\text{Total time}} = \frac{100\, m}{15\, s} \approx 6.67\, m s^{-1}$.

Explore More

Similar Questions

What conclusion can you draw from the displacement$-$time graph of a body as shown below?

$A$ particle accelerates from rest at a constant rate for some time and attains a constant velocity of $8\, m s^{-1}$. Afterwards,it decelerates at a constant rate and comes to rest. If the total time taken is $4\, s$,the distance travelled is:

What can you say about the motion of a body if its displacement$-$time graph is a straight line parallel to the time axis?

$(a)$ Differentiate between speed and velocity.
$(b)$ When is a body said to have uniform velocity?
$(c)$ How can we describe the position of an object? Illustrate with a suitable example.

The direction of acceleration of an object moving in a circular path is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo