The density rho versus volume V graph is show | vedclass

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(C) From the given $(\rho - V)$ graph,we observe that for processes $AB$ and $CD$,the volume $V$ is constant. Therefore,$AB$ and $CD$ are isochoric pr

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(C) From the given $(\rho - V)$ graph,we observe that for processes $AB$ and $CD$,the volume $V$ is constant. Therefore,$AB$ and $CD$ are isochoric processes.In an isochoric process,the pressure $P$ is directly proportional to the temperature $T$ $(P \propto T)$,which means the graph of $P$ versus $T$ should be a straight line passing through the origin.For processes $BC$ and $AD$,the density $\rho$ is constant. Since $\rho = \frac{m}{V}$,constant density implies constant volume,which contradicts the graph. However,looking at the provided options,the graph $D$ represents processes where $AB$ and $CD$ are vertical lines (isochoric) and $BC$ and $AD$ are curves. Re-evaluating the graph: $AB$ and $CD$ are vertical lines in the $(\rho - V)$ graph,meaning they are isochoric. In the $(P - T)$ graph,isochoric processes must be straight lines passing through the origin. Option $D$ shows $AB$ and $CD$ as vertical lines,which is incorrect. Option $C$ shows $AB$ and $CD$ as straight lines passing through the origin,which is the correct representation for isochoric processes.

The density $\rho$ versus volume $V$ graph is shown in the figure. Find the corresponding pressure $P$ versus temperature $T$ graph.

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