Dimethyl glyoxime forms a square planar complex with $Ni^{2+}$. This complex should be

  • A
    diamagnetic
  • B
    paramagnetic having $1$ unpaired electron
  • C
    paramagnetic having $2$ unpaired electrons
  • D
    ferromagnetic

Explore More

Similar Questions

The spin-only magnetic moment of $[MnBr_4]^{x-}$ is $5.9 \ BM$. The geometry of the complex and $x$ respectively are

Which of the following statements is incorrect for $K_3[CoF_6]$?

Which of the following complexes does not match with the hybridization state of its metal ion?
$(i) [Ni(CO)_4], sp^3$
$(ii) [Ni(CN)_4]^{2-}, sp^3$
$(iii) [CoF_6]^{3-}, d^2sp^3$
$(iv) [Fe(CN)_6]^{3-}, sp^3d^2$

Match the coordination number and type of hybridisation with the distribution of hybrid orbitals in space based on Valence Bond Theory.
Coordination number and type of hybridisation Distribution of hybrid orbitals in space
$a. 4, sp^3$ $i. \text{trigonal bipyramidal}$
$b. 4, dsp^2$ $ii. \text{octahedral}$
$c. 5, sp^3d$ $iii. \text{tetrahedral}$
$d. 6, d^2sp^3$ $iv. \text{square planar}$

Select the correct option.

Match List-$I$ with List-$II$:
List-$I$ (Tetrahedral Complex) List-$II$ (Electronic configuration)
$A$. $TiCl_4$ $I$. $e^2, t_2^0$
$B$. $[FeO_4]^{2-}$ $II$. $e^4, t_2^3$
$C$. $[FeCl_4]^{-}$ $III$. $e^0, t_2^0$
$D$. $[CoCl_4]^{2-}$ $IV$. $e^2, t_2^3$

Choose the correct answer from the options given below:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo