Domain of the function f(x) = frac{x^2 - 3x + | vedclass

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(D) The given function is $f(x) = \frac{x^2 - 3x + 2}{x^2 + x - 6}$.Factorizing the numerator: $x^2 - 3x + 2 = (x - 2)(x - 1)$.Factorizing the denomin

Vedclass · Accepted Answer

$\{x : x \in R, x 
eq 2, x 
eq -3\}$

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(D) The given function is $f(x) = \frac{x^2 - 3x + 2}{x^2 + x - 6}$.Factorizing the numerator: $x^2 - 3x + 2 = (x - 2)(x - 1)$.Factorizing the denominator: $x^2 + x - 6 = (x + 3)(x - 2)$.Thus,$f(x) = \frac{(x - 2)(x - 1)}{(x + 3)(x - 2)}$.The function is defined for all real values of $x$ except where the denominator is zero.Setting the denominator to zero: $(x + 3)(x - 2) = 0$,which gives $x = -3$ or $x = 2$.Therefore,the domain of the function is the set of all real numbers except $2$ and $-3$.Domain = $\{x : x \in R, x 
eq 2, x 
eq -3\}$.

$x$	$-4$	$-3$	$-2$	$-1$	$0$	$1$	$2$	$3$	$4$
$y = f(x) = x^2$

Domain of the function $f(x) = \frac{x^2 - 3x + 2}{x^2 + x - 6}$ is

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