The dot product of two mutually perpendicular | vedclass

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(A) The dot product of two vectors $\vec{A}$ and $\vec{B}$ is defined as $\vec{A} \cdot \vec{B} = |A||B| \cos 	heta$,where $	heta$ is the angle betw

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(A) The dot product of two vectors $\vec{A}$ and $\vec{B}$ is defined as $\vec{A} \cdot \vec{B} = |A||B| \cos 	heta$,where $	heta$ is the angle between the vectors.Since the vectors are mutually perpendicular,the angle $	heta = 90^\circ$.Substituting this into the formula,we get $\vec{A} \cdot \vec{B} = |A||B| \cos 90^\circ$.Since $\cos 90^\circ = 0$,the dot product is $|A||B| 	imes 0 = 0$.

The dot product of two mutually perpendicular vectors is:

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