Draw the graph of p(x) = x^{2} + x - 12 and f | vedclass

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(C) To find the zeros of the polynomial $p(x) = x^{2} + x - 12$,we set $p(x) = 0$.Thus,$x^{2} + x - 12 = 0$.Factoring the quadratic equation,we look f

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$-4, 3$

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(C) To find the zeros of the polynomial $p(x) = x^{2} + x - 12$,we set $p(x) = 0$.Thus,$x^{2} + x - 12 = 0$.Factoring the quadratic equation,we look for two numbers that multiply to $-12$ and add to $1$.These numbers are $4$ and $-3$.So,$x^{2} + 4x - 3x - 12 = 0$.$x(x + 4) - 3(x + 4) = 0$.$(x - 3)(x + 4) = 0$.Setting each factor to zero,we get $x - 3 = 0$ or $x + 4 = 0$.Therefore,$x = 3$ or $x = -4$.The zeros of the polynomial are $-4$ and $3$.

Draw the graph of $p(x) = x^{2} + x - 12$ and find the zeros of this polynomial.

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