Due to the flow of current in a circular loop | vedclass

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(B) The magnetic field at the centre of a circular loop of radius $R$ carrying current $I$ is given by $B = \frac{\mu_0 I}{2R}$.From this,we can expre

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$2 \pi B R^3 / \mu_0$

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(B) The magnetic field at the centre of a circular loop of radius $R$ carrying current $I$ is given by $B = \frac{\mu_0 I}{2R}$.From this,we can express the current $I$ as $I = \frac{2BR}{\mu_0}$.The magnetic moment $M$ of a current loop is defined as $M = I 	imes A$,where $A$ is the area of the loop.For a circular loop,$A = \pi R^2$.Substituting the expression for $I$ into the formula for $M$,we get:$M = \left( \frac{2BR}{\mu_0} ight) 	imes (\pi R^2) = \frac{2 \pi B R^3}{\mu_0}$.

Due to the flow of current in a circular loop of radius $R$,the magnetic field produced at the centre of the loop is $B$. The magnetic moment of the loop is:

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